Question

please give the answer please

Answer 1

Answer:

In Triangle AOB, Angle 0 = 90°

AB²= AO²+BO²..........Pythagoras theorem

13² = A0² + 5²

169. = AO² +25

169-25 = AO²

144. = AO²

12 =AO

Now in triangle AOC

AC²= AO²+OC²

15² = 12² +OC

225 = 144 + OC²

225-144 =OC²

81. = OC

9 = OC

now we have to find BC

but BC= BO+ OC

5+9

BC= 14.

Hope it will help you ❤️