Math, asked by apnatvaagarwal7, 5 months ago

please give the answer step by step ​

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Answered by dandi19
1
Solution:

axy^2 + 3x + 2a^2y^2 + 6a

Let’s rearrange the polynomials

2a^2y^2 + axy^2 + 6a + 3x

Factor by grouping

(2a^2y^2 + axy^2) + (6a + 3x)

Factor out the common

(2a^2y^2 + axy^2) = ay^2

(6a + 3x) = 3

Then

ay^2 (2a + x)

3 (2a + x)

Therefore, the factor of axy^2 + 3x + 2a^2y^2 + 6a is (ay^2 + 3) (2a + x)

Hope this will help.

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