Please give the answer with complete method
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Hope this helps
pOH = -log(OH- ions)
=>pOH = -log(2 × 5 × 10^-6)
This is because after dissociation of Ba(OH)2, we'll get 2 times the concentration of Ba(OH)2 in OH- ions. Therefore,
=>pOH = 5
Now, pOH + pH = 14 (look it up), therefore
pH = 14 - 5, ie, 9, thus,
pH = 9
Peace.
pOH = -log(OH- ions)
=>pOH = -log(2 × 5 × 10^-6)
This is because after dissociation of Ba(OH)2, we'll get 2 times the concentration of Ba(OH)2 in OH- ions. Therefore,
=>pOH = 5
Now, pOH + pH = 14 (look it up), therefore
pH = 14 - 5, ie, 9, thus,
pH = 9
Peace.
purveshsohony2006:
Thanks a lot
You're welcome
Peace
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