Question

Please give the answer with detailed solution

Answer 1

Let and are linear charge densities of two parallel wires.

electric field due to at r distance is given by

now, force experienced by wire of linear charge density is

where q =

now, F =

and force per unit length,

now , putting = 3 × 10^-8 C/cm = 3 × 10^-6 C/m , r = 2cm = 0.02m

so, F' = (3 × 10^-6)²/(2 × 3.14 × 8.85 × 10^-12 × 0.02)

= 9 × 10^-12/(6.28 × 8.85 × 2 × 10^-14)

= 0.08 × 10²

= 8 N/m

so, workdone against electrostatic force per unit length = F' × s

= 8N/m × 1cm

= 8 N/m × 0.01m

= 0.08 J/m

= 8/100 J/m

hence, value of x = 8

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