Math, asked by bt1981silveroaksbt, 5 hours ago

Please give the answers of the given Questions​

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Answered by SAB0108
0

14)

length(l)= 8cm

width(w)= 6cm

length of diagonal of a rectangle =

 \sqrt{l {}^{2}  + b { }^{2} }

 \sqrt{8 ^{2} + 6^{2} }

 \sqrt{64 + 36}

 \sqrt{100}

= 10 cm is the diagonal

15)

diagonal(d) =

8 \sqrt{2}

diagonal of a square =

 \sqrt{2 \times side ^{2} }

8 \sqrt{2}  =  \sqrt{2 \times side ^{2} }

If we square both sides,

128= 2 × side × side

64= side^2

side=

 \sqrt{64}

= 8cm

Side of square is 8cm

Area of a square is side× side

=8 × 8

=64 cm2

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