Question

Please give the correct answer.​

Answer 1

Correct option is

B

μ

k

=1−

n

2

1

d=

2

1

(g sinθ)t

1

,

d=

2

1

(g sinθ−μg cosθ)t

2

t

1

=

g sinθ

2d

t

2

=

g sinθ−μg cosθ

2d

According to question, t

2

=nt

1

n

g sinθ

2d

=

g sinθ−μg cosθ

2d

μ, applicable here, is kinetic friction as the block moves over the inclined plane.

n=

1−μ

k

1

(

∵cos 45

∘

=sin 45

∘

=

2

1

)

n

2

=

1−μ

k

1

or 1−μ

k

=

n

2

1

Or μ

k

=1−

n

2

1

hope this will help you

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