Question

Please give the correct solution copied theory or answer will be reported​

Answer 1

Answer:

B

Explanation:

There are a total of 10^6 cells.Each cell divides.

After 2 doubling times there will be 4×10^6 cells.Now each cell has 1000 base pairs.The probability of getting a mutation is 10^-9.

If each cell has 1000 bp then 4×10^6 cells will have 4×10^9 base pairs.

Now use the probability here.

In a total of 4×10^9 bp there are 1 in 10^9 chances chances that mutation will occur.

so there are 4 in 4×10^9 chances that mutation will occur.

Now there 4 mutations can occur in bp of any cell even in a single cell.

so a mximum of 4 mutant cells can be made if all the 4 mutations occur in different cells and not the same. I hope you understood.