please give the explanation ans is 4th one❤❤
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Answered by
21
Answer:
The correct option is B.
Given,
A force F is applied along a rod of transverse sectional area A,
Force is F
Area is A
The normal stress is given as p cos \thetapcosθ
Where, p is pressure.
And is given as p =
Hence, normal stress =
I hope this will help ❤
Answered by
0
Answer:
Correct option is B F/Acos^2
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