Question

please give the first answer ​

Answer 1

The equations of lines are:

$\sqrt{3} x + y = 1$

$x + \sqrt{3} y = 1$

From equation No:01 and 02...

$y = - \sqrt{3} x + 1 \\ y = \frac{ - 1}{ \sqrt{3} }x + \frac{1}{ \sqrt{3} }$

Slopes are...

$m1 = - \sqrt{ 3} \\ m2 = - \frac{1}{ \sqrt{3} }$

Putting these value in formula we get:

Angle = 30 degree