Question

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Answer 1

Question :

A is twice old as B. five years ago a was three times as old as B, find their present age.

Answer:

• Age of A = 20 years

• Age of B = 10 years

Given :

• A is twice old as B.

• 5 years ago a was three times as old as B.

To find :

• Their present age =?

Step-by-step explanation:

Let the age of A be x years

And, the age of B be, y years old

Then,

According to the question :

x = 2y ..... (1)

x − 5 = 3 ( y − 5 ) ...... (2)

from equation(1) and equation(2)

➟ 2y − 5 = 3y − 15

➟ 2y - 3y = - 15 + 5

➟ -y = - 10

➟ y = 10

Hence, the value of y = 10.

Putting value of y in equation (1)

➟ x = 2y

➟ x = 2 × 10

➟ x = 20.

Hence,

Age of A = x = 20 years

Age of B = y = 10 years

Answer 2

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Given :-

• A is twice the age of B
• Five years ago A was 3 times as old as B

To find :-

current age of both

Step by step explanation :-

current situation :-

a = 2b----------------(i)

5 years ago

A's age = a-5

B's age = b-5

(a-5)= 3(b-5)

a-5=3b-15

a-3b = -15 + 5

a-3b = -10

putting value of a of eq(i) in eq (ii)

2b-3b=-10

-b = -10

b = 10years

putting value of b in eq (i)

a = 2 x 10

a = 20 years

Answer :-

A's age = 20 years

B's age = 10 years

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