please give the full solution
Answers
Step-by-step explanation:
hey mate
let the unit digit be x
and the tens digit be y
then. assuming x>y
Applying the first condition we get
x-y= 5--------------(i)
now
Number formed = 10y+x
Interchanged number = 10x+y
Applying second condition we get
10x+y+10y+x= 99
=> 11x+11y=99
=> 11(x+y)=99
=> x +y= 99/11
=>x+y= 9
now in the first equation
x-y= 5. [ Adding both equations ]
x+y= 9
2x= 14
=>x = 7
Now y = x-y= 5=> 7-y= 5=>-y= 5-7
=>-y= -2
=>y= 2
so
Original number is 10y+x = 10*2+7 = 20+7= 27
hope it helps ✌
Answer:
One'digit =x
Ten's digit=10(x+5)
=10x+50
Adding them
x+10x+50
=11x+50
Interchanging. them
One'digit=x+5
Tens's digit= 10(x)
= 10x
Adding them
x+5+10x
=5+11x
Adding the original and resulting number
11x+50+5+11x=99
22x+55=99
22x=99-55
22x= 44
x=2
Hence
One digit=2
ten's digit=2+5
=7
The number can be either 27 or 72
Also,by adding the numbers ,we get 99..