Question

please give the solution along with the steps of solving.​

Answer 1

Answer:

b 10 to the power 16 because in one second

Answer 2

Question :

A current of 1 A is drawn by a filament of an electric bulb. Number of electrons passing through a cross section of the filament in 16 seconds would be ?

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Given :

• Current (I) = 1 Ampere
• Time interval (t) = 16 s

To Find :

• Number of electrons passing through bulb

Solution :

We know that,

⇒I = Q/ t

Where,

• I is current
• Q is charge
• t is time

⇒Q = IT

⇒Q = 1*16

⇒Q = 16

$\therefore$ Charge of the bulb is 16 C

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Now, use formula for quantization of charges :

⇒Q = ±ne

⇒16 = n * ( 1.6 * 10^{-19})

⇒n = 16/(1.6 * 10^{-19})

⇒n = 16/(16 * 10^{-20})

⇒n = 1/10^(-20)

⇒n = 10^(20)

$\therefore$ Number of electrons passing through bulb are $\sf{10 ^{20}}$