Question

Please give the solution if. U can line by line.... It's urgent... I will mark as brainliest.... ​

Answer 1

Answer:

Let us assume that originally Meena had X rupees and Y 20 paise coins. Going shopping she had (100 X + 20 Y) paise

She returned with only (100 y +20 x) paise.

This last sum, as we know, is one –third of the original and therefore

3(100 Y +20 X) = 100X + 20 Y

Simplifying we have X= 7 Y

If Y is 1 then X is 7. Assuming this so Meena had 7.20 rupees when she set out for shopping.

This is wrong because Meena actually had about 15 rupees.

Let us see now what we get if Y= 2. Then X= 14.

The original sum was 14.40 rupees which accords with the condition of the problem.

If we assume that Y= 3 then the sum will be too big - 21.6 rupees.

Therefore the only suitable answer is 14.40 rupees.

After shopping Meena had 2 one rupee notes and 14 twenty Paise coins.

This is actually 1/3rd of the original sum 1.440: = 480.

Meena’s purchases, therefore, cost 14.40 – 4.80 = Rs. 9.60

hope it helps you my friend