Question

Please give the solution of the following question only correct answer required ‼️

CHAPTER- QUADRATIC EQUATIONS IN ONE VARIABLE CLASS 10 ICSE BOARD ‼️​

Answer 1

Answer:

this is the correct answer

I also have verify this answer

Answer 2

$\huge \fbox \green{❤Answer:}$

Given:

$\frac{x - 2}{x + 2} + \frac{x + 2}{x - 2} = 4$

To Find:

$The \: Value \: of \: x$

$\huge \fbox \pink{Solution:}$

$\frac{x - 2}{x + 2} + \frac{x + 2}{x - 2} = 4$

$⇒ \frac{(x - 2 {)}^{2} + (x + 2 {)}^{2} }{ {x}^{2} - 4} = 4$

$⇒ {x}^{2} + 4 - 4x + {x}^{2} + 4 + 4x = 4 {x}^{2} - 16$

$⇒{2x}^{2} + 8 = 4x - 16$

$⇒24 = {2x}^{2}$

$⇒ {x}^{2} = 12$

$∴x = 2 \sqrt{3}$

$Hence \: The \: Value \: of \: x = 2 \sqrt{3}$

$\\ \\ \\ \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}$