Question

PLEASE GIVE THE WELL EXPLAINED ANSWER​

Answer 1

option C is the answer...

Answer 2

Answer:

(a) For simple pendulum , K is proportional to mass m of particle . hence, m/K becomes constant and doesn't effect the time period .

(b) for small angle sin∅ ≈∅ but for large angle sin∅ < ∅ . since this factor is multiplied to the restoring force ' mgsin∅' is replaced by ' mg∅' . which means effective reduction in g for large angle .

Hence, an increase in time period T over that given by

T = 2π√{L/g}

compare to the case which it is assumed sin∅ = ∅

(c) yes , actually the motion of hands of a wristwatch to indicate time depends on action of the spring and has nothing to do with acceleration due to gravity . you can say that wristwatch is independent of acceleration due to gravity .

(d) in free fall body effective g = 0 . that is gravity is disapear . ( I mean weightless)

So, T = 2π√( L/g)

= 2π√(L/0) = ∞

Hence, frequency = 1/T = 1/∞ = 0