Question

please give your answer in photo

Answer 1

Answer :

x = 5 , y = 6

Solution :

(Using elimination method)

Here ,

The given equations are ;

• ⅗x - ⅔y + 1 = 0 → ⅗x - ⅔y = -1 -------(1)

• ⅖x + ⅓y = 4 ------(2)

Now ,

Multiplying eq-(2) by 2 , we have ;

=> 2•(⅖x + ⅓y) = 2•4

=> ⅘x + ⅔y = 8 -------(3)

Now ,

Adding eq-(1) and (3) , we have ;

=> (⅗x - ⅔y) + (⅘x + ⅔y) = -1 + 8

=> ⅗x + ⅘x = 7

=> (⅗ + ⅘)x = 7

=> ⁷⁄₅x = 7

=> x = 7•⁵⁄₇

=> x = 5

Now ,

Putting x = 5 in eq-(2) , we get ;

=> ⅖x + ⅓y = 4

=> ⅖•5 + ⅓y = 4

=> 2 + ⅓y = 4

=> ⅓y = 4 - 2

=> ⅓y = 2

=> y = 2•3

=> y = 6

Hence ,

x = 5 , y = 6

Answer 2

Given:-

• $\sf\dfrac{3x}{5}-\dfrac{2y}{3}+1$ = 0
• $\sf\dfrac{2x}{5} + \dfrac{1y}{3} - 4 = 0$

To find:-

• values of X and y

Solution:-

let's take the L.C.M of both the equations:-

$\implies$ $\sf\dfrac{9x-10y+15}{15}$ = 0

$\implies$ $\sf 9x-10y+15 = 0$ ... $\sf eq_{1}$

$\implies$ $\sf\dfrac{6x+15y-60}{15}$ = 0

$\implies$ $\sf 6x+15y-60=0$ ... $\sf eq_{2}$

Multiplying the entire eq.2 by 2

$\sf 2[6x+5y-60] = 0$

$\sf 12x+10y-120=0$ ... 3rd eq

Now, adding 3rd equation with eq1

$\implies$ $\sf 9x-10y+15+12x+10y-120=0$

$\implies$ $\sf 9x-10y+15+12x+10-120=0$

$\implies$ $\sf 21x-105 = 0$

$\implies$ x = 5

now, putting the value of x in eq. 2

$\implies$ 9(5)-10y+15 = 0

$\implies$ 45-10y+15 = 0

$\implies$ -10y = -60

$\implies$ y = 6