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Step-by-step explanation:
at B, we find straight angle which measures 180°
as, angle A in ∆ABC is 70°
as, opposite angles in same parallel line are supplementary
Angle A in ∆ABC + Angle B in ∆ABD = 180°
70° + Angle B = 180°
Angle B = 180° - 70° = 110°
so, angle B in ∆ABC + angle B in ∆ABD = 180°
ANGLE B + 110° = 180°
Angle B = 180° - 110° = 70°
sso,
In ∆ABC,
y + 70° + 70° = 180° { angle sum property }
y + 140° = 180°
y= 40°
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