Question

please giveme this question answer

slove the following inequalities​

Answer 1

6x−54x+16x−54x+1 < 0 on putting (6x – 5) and (4x + 1) equal to zero, we get the critical points as x=56x=56 and x=−14x=−14. On the real number line they can be shown as:

• When x<−14x<−14, both numerator and denominator of the expression 6x−54x+16x−54x+1 are negative making the expression positive

• When xx lies between −14−14 and 56,56, the expression 6x−54x+16x−54x+1 becomes negative, hence less than zero.

• When x>56x>56, both (6x – 5) and (4x + 1) are positive, making the expression 6x−54x+16x−54x+1 positive and hence greater than zero.

∴ For 6x−54x+16x−54x+1 < 0, xx ∈ (−14,56)(−14,56).

hope it will help you bro

Answer 2

Step-by-step explanation:

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