please gugs answers this questions with process :-(find the value of AB)
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Answer:
tan Φ = opposite / adjacent
in Δ BCD
BC= 10m
tan 45°= BC/DC
1= 10/DC
DC=10m
By Pythagoras theorem
BC²+DC²=BD²
10² + 10² = BD²
2(10)²=BD²
BD=√2(10)²
BD=10√2m
Now , in ΔABD
tan 30°= AB/BD
√3 = AB/10√2
AB= √3(10√2)
AB= 10(√6)
AB=10√6m
Answered by
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Answer:
In ∆BCD, /_C=90°
Sin D=opposite side/hypotenuse
Sin45°=10/BD
1/√2=10/BD
BD=10√2cm
In ∆ABD,/_=90°
tan D=opposite side/adjacent side
tan 30°=AB/10√2
1/√3=AB/10√2
AB×√3=10√2
AB=10√2/√3
multiply both numerator and denominatorby √3
=10√2×√3/√3×√3
=10√6/3
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