Question

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Answer 1

[5ab(-a+b+3c)]-[3a(a+b+c) - (2ab(a-b+2c)]

$[5ab(-a+b+3c)] - [3a(a+b+c) - (2ab(a-b+c)] \\ ( - 5 {a}^{2} b + 5a {b}^{2} + 15abc) - ({3a}^{2} + 3ab + 3ac - {2a}^{2} b + {2a}{b}^{2} - 4abc) \\ \\ - 5 {a}^{2} b + 5a {b}^{2} + 15abc - 3 {a}^{2} - 3ab - 3ac + 2 {a}^{2} b + 2a {b}^{2} + 4abc \\ = - 3 {a}^{2} b + 7a {b}^{2} + 19abc- 3 {a}^{2} - 3ab - 3ac$

Once again sorry for the misbehaviour.

Answer 2

Answer:

-5a^2b+5ab^2+15abc-3a^2b-3ab^2-3abc+2a^2b^2-ab^3+4ab^2c-8a^2b+2ab^2+12abc2a^2b^2-2ab^3+4ab^2c

Step-by-step explanation:

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