Math, asked by rose1857, 5 months ago

Please guy's help me with no. 2​

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Answered by roshni2262
5

Answer:

area \: of \: lawn \:  = l \times b \\  \:  \:  \:  \:  = 80 m\times 60m \\  \:  \:  = 4800 {m}^{2}  \\  \\ area \: of \: swimming \: pool \:  =  \: l \times b \\  \:  \:  = 20m \times 6m \\   \:  \:  = 120 {m}^{2}  \\  \\ area \: of \: land \: where \: grass \: is \: to \: be \: put \:  \\  = 4800 {m}^{2}  - 120 {m}^{2}  \\  = 4680 {m}^{2}  \\  \\ cost \: of \: putting \: grass \: in \: the \: feild \:  = 4680 \times 30 \\  = rs \: 1200

Answered by nehagupta5
3

Answer:

hello..

I remember you..

Why did you block me??

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