Question

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Answer 1

80 N is the required answer.

GIVEN:

• Mass of the object , m = 200 kg
• Initial velocity , u = 8 m/s
• Final velocity , v = 12 m/s
• Time , t = 10 sec

TO FIND:

Magnitude of force, f

FORMULAE:

• According to Newton's second law of motion, f = ma

• According to first equation of motion, v = u + at

SOLUTION:

STEP 1: TO FIND ACCELERATION

$v = u + at \\ \\ 12 = 8 + 10a \\ \\ 10a = 12 - 8 \\ \\ 10a = 4 \\ \\ a = \frac{4}{10} \\ \\ a = \frac{2}{5} \\ \\ a = 0.4 \: \frac{m}{ {s}^{2} }$

Acceleration is 0.4 m/s²

STEP 2: TO FIND FORCE

$f = ma \\ \\ f = 200 \times 0.4 \\ \\ f = 20 \times 4 \\ \\ f = 80 \: newton$

ANSWER:

Magnitude of force exerted on the object is 80 N.

DIRECT FORMULA:

Force, f = m (v - u )/ t

FORCE:

• Force is defined as the product of mass and acceleration.

• f = ma is the result of Newton's second law of motion.

• Newton's second law of motion states that force is equal to the rate of change of momentum. f = dp/dt

THREE EQUATIONS OF MOTION:

• First equation of motion , v = u + at.

• Second equation of motion, s = ut + (at²)/2

• Third equation of motion, v²- u² = 2as

• Three equations of motion can be applied only if acceleration is constant.