please guys answer this, it's urgent!!
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Clearly the roller is a right circular cylinder of height h=120 cm
and radius of its base =r=42 cm
∴ area covered by the roller in one revolution = curved surface area of the roller
=2×22/7×42×120cm2=31680cm2
so, area covered by the roller is 500 revolution = (31680×500)cm2
=100×31680×500/100×100m2=1584m2
So the are of the playground is 1584m²
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Holla mate
the answer is on the above attachment.
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Hope it's help uh ..
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