Question

Please guys answer this question
It's very urgent
I'll mark as brainliest
It's a 100 point question

Answer 1

heya!! mate^_^

your answer is - - - - -

$Aman's\:Method$

hexagon will be divided into 2 equal trapezium

Formula to find

area of trapezium = 1/2 (sum of parallel sides)height

=1/2×(11+5)×4

=1/2×16×4

=32cm×2 =

$64cm^2$

________________________

$ridhima's\:method$

hexagon will be divided into 2 triangle and a rectangle

area of rectangle=8×5=40cm

area of triangle= 1/2×base×height

= 1/2×8×3

=12cm×2=

$24cm^2$

area of hexagon=40+24=64 cm

$=64cm^2$

Answer 2

method of aman
area of trapezium equal to
half into 11 plus 5 *4
=32*2
=64
area of hexagon is 64sqcm
ridhimas method
area of rectangle
equal to
8*5=40
area of triangle =1/2 * b.h
=1/2.8*2
=24
adding both we get area of hexagon eual to64sqcm