please guys anyone having question paper class 12th 2016 math
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bhaiya igive image ssee them it help u
both hindi and english
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Step-by-step explanation:
Given, size of carpet=5×2m
2
and width of border=25cm=
100
25
=0.25m
∴ Area of carpet ABCD=AB×BC=5×2=10m
2
because area of rectangle= length × breadth.
So, length of inner blue portion,EF=AB−(2×0.25 cm)=5−0.50=4.5m
and breadth of inner blue portion FG=BC−(2×0.25)=2−0.50=1.5m
Area of blue portion=Area of rectangleEFGK=EF×FG=4.5×1.5=6.75m
2
Now, area of red porion=Area of ABCD−Area of EFGH=10−6.75=3.25m
2
∴ Ratio of areas of red portion to blue portion=3.25:6.75=13:27
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