Question

please guys do answer this question​

Answer 1

Step-by-step explanation:

x+2y+(2x-3y)i+4i=5

x+2y-5+2xi-3yi+4i=0

(x+2y-5)+i(2x-3y+4)=0

compare real & imaginary part

x+2y-5=0 & 2x-3y+4=0

x=5-2y______(1)

now, 2(5-2y)-3y+4=0

10-4y-3y+4=0

-7y=-14

y=2

putting the value of y in eqn. (1)

x=5-2.2

x=1

so, x=1&y=2

Answer 2

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