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this is your answer.now do your promise.
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Step-by-step explanation:
I) take x, y are common,we get
xy[4x+12z+20y]
take 4 as common, we get,
4xy[x+3z+5y]
write in the order
= 4xy[x+5y+3z] this is the answer for first one.
ii) take a as common and b as common
= a(6a+3c) –b(12a+6c)
= a(6a+3c) –2b(6a+3c)
= (a–2b) (6a+3c) is the factors for 2nd one
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