Question

Please guys give me the right answer.

step by step explanation

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Answer 1

1. write

$( \frac{ \sqrt[3]{ {x}^{4 } \times y } }{ \sqrt[3]{x \times {y}^{7} } } )$

under the power of -4

2. take out x from numerator and y^2 from denominator and cancel √xy that remains

$\frac{x \sqrt[3]{xy} }{ {y}^{2} \sqrt[3]{xy} }$

Now to remove the negative exponent write the reciprocal of the expression and raise it to power 4

3. The final answer will be

$\frac{ {y}^{8} }{ {x}^{4} }$

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