please guys
give the answer of my questions
prove that AB || CD,CD||EF, AB||EF
and also justify the answer
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i)angle BCD=angle BCE+angle ECD
=20+30=50
angle ABC=angleBCD
(alternative interior angles)
therefore AB||CD
ii) angle ECD+angle CEF=30+150=180°
(INTERIOR ANGLES SUPPLEMENTARY)
THEREFORE CD||EF
iii)AB||CD,CD||EF
=>AB||EF
(two lines parallel to the same given line are parallel to each other)
HENCE PROVED!!!!!
=20+30=50
angle ABC=angleBCD
(alternative interior angles)
therefore AB||CD
ii) angle ECD+angle CEF=30+150=180°
(INTERIOR ANGLES SUPPLEMENTARY)
THEREFORE CD||EF
iii)AB||CD,CD||EF
=>AB||EF
(two lines parallel to the same given line are parallel to each other)
HENCE PROVED!!!!!
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