Question

please guys help me with this question with full explanation
correct answer will be marked as brailiest and will be given 5 stars and thanks
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Answer 1

GIVEN :-

• The of a two digit number are such that one is twice the other .
• When the digits are interchanged, the new number obtained is greater than the original number by 27.

TO FIND :-

• The original number.

SOLUTION :-

Let the tens place digit of a two digit number be "x". Hence the ones place digit of a two digit number be "2x".

⇏Original Number = 10 ( Tens Place digit ) + Ones Place digit.

⇏Original Number = 10 × x + 2x

⇏Original Number = 10x + 2x

⇏Original Number = 12x.

Now according to the question the numbers are interchanged so,

⇏New Number = 10 ( Ones Place Digit ) + Tens Place digit

⇏New Number = 10 × 2x + x

⇏New Number = 20x + x

⇏New Number = 21x

Now according to the question we have,

⇏New Number = Original number + 27

⇏21x = 12x + 27

⇏21x - 12x = 27

⇏9x = 27

⇏x = 27/9

⇏x = 3

Therefore , original number = 12x = 36.

Answer 2

36 and 63

Let us assume digits be x and 2x.

So the numbers are: 10+2x and 20x+x.

Difference 27, hence : 27 + 10x+ 2x = 20x+x

Giving us 27 = (21–12)x => 27 = 9x = > 3

Therefore numbers are 36 and 63

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