Question

PLEASE GUYS ITS A QUESTION OF A.P HELP ME WITH THIS

Q.35

NO SPAMMING PLEASE.

Answer 1

First term ( a ) = 17

Common difference ( d ) =

$14\frac{1}{2} - 17$

$\frac{29}{2} - 17 = \frac{29 - 34}{2} = \frac{ - 5}{2}$

an = ( - 28 )

• an = a + ( n - 1 )d

- 28 = 17 + ( n - 1 ) × ( -5/2 )


$- 28 = 17 - \frac{ 5n}{2} + \frac{5}{2}$

$- 28 = \frac{ 34 - 5n + 5}{2}$


- 56 = 39 - 5n

- 95 = - 5n

19 = n

( - 28 ) is the 19th term of the AP.

Answer 2

a1=a=17
a2=14.5
d=a2-a1
d=17-14.5
d=2.5
a(n)=a+(n-1)d
-28=17+(n-1)2.5
-28=17+2.5n-2.5
2.5n=-28-19.5
2.5n=-47.5
n=47.5/2.5
n=19
hope it helps you
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