Question

Please guys... number iv (4)

Maths Aryabhattas... Help me out!!!

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Answer 1

Answer:

AD/AB =8/15

DB=15-8=7

AD/DB=AE/EC

=>8/7=AE/3.5

=>AE=8*3.5/7=4

Answer 2

Answer:

Here, The value of AE in the given triangle in (iv part) is 3.06cm.

Step-by-step explanation:

Here, As per our given question,

As we have in triangle ABC,

=AD/AB=8/15, EC=3.5cm, and DE ll BC

So, AD/AB=AE/AC (By Thales' Theorem)

Let here the value of AC be x

So,=8/15=3.5/x

On cross-multiplying between both sides, we get,

=8x=3.5×15

=8x=52.5

=x=52.5/8

=x=6.56

So, Now AC=6.56cm

So, AE=AC-EC

=6.56-3.5

=3.06

So, The value of AE in the given triangle is 3.06cm.

Thank you.