Question

Please guys nywn solve it for me..I'm in need its very urgent!!!!​

Answer 1

Step-by-step explanation:

Correction :-

Find the value of x³-(3x)³ -27 or

x³-(27/x³)-27?

Given :-

x-(3/x) = 3

To find:-

Find the value of x³-(27/x³) -27 ?

Solution :-

Given that :

x-(3/x) = 3 ---------(1)

On cubing both sides then

=> [x-(3/x)]³ = 3³

We know that

(a-b)³ = a³-b³-3ab(a-b)

=> x³-(3/x)³ -3(x)(3/x)[x-(3/x)] = 27

=> x³-(27/x³)-3(3x/x)[x-(3/x)] = 27

=> x³-(27/x³)-3(3)[x-(3/x)] = 27

=> x³-(27/x³)-9[x-(1/x)] = 27

=> x³-(27/x³)-9(3) = 27 (from (1))

=> x³-(27/x³)-27 = 27

=> x³-(27/x³) -27= 27

Answer:-

The value of x³-(27/x³)-27 is 27

Used formulae:-

→(a-b)³ = a³-b³-3ab(a-b)

Answer 2

Answer:

I feel the question is wrong or x^3-1/x^3=27

Step-by-step explanation:

x-3/x =3

do cube on both side

[x-3/x]^3 =27

(a-b)^3= a^3-b^3-3ab(a-b)

a=x, b= 3/x

substituting above

x^3-27/x^3-3*x *3/x (x-3/x)

x^3-27/x^3-9[3]= 27

x^3-27/(x^3)=54