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The taxi fare in a city is as follows: For the first kilometre, the fare is 5 and for the subsequent distance it is 4 per km. Taking the distance covered as x km and total fare as Rs.y, write a linear equation for this information and draw its graph.
Answer:
GIVEN
- Taxi fare for first kilometer = Rs.5
- Taxi fare for subsequent distance = Rs. 4
- Total distance covered =x
- Total fare =y
SOLUTION
Since the fare for first kilometer = Rs.5
According to problem,
Fare for (x–1) kilometer =4(x-1)
So, the total fare y=4(x-1)+5
⇒y=4(x−1)+5
⇒y=4x–4+5
⇒y=4x+1
Hence, y=4x+1 is the required linear equation.
Now the equation is y=4x+1 ...(1)
- Now, putting the value x=0 in (1)
y=1
- Putting the value x=2 in (1)
y=4(2)+1
y=9
graph is in attachment
NOT A COPIED CONTENT
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