Math, asked by sunilkumarpchq82, 7 hours ago

please guys solve this question

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Answered by Anonymous
1

Answer:

x = 3, y = 4.

Step-by-step explanation:

The given system of equations is

3x−y+711+2=10 ...(i)

2y+x−117=10 ....(ii)

From (i), we get

33x−y−7+2211=10

⇒ 33x−y+15=10×11

⇒ 33x+15−110=y

⇒ y=33x−95

From (ii), we get

14y+x+117=10

⇒ 14y+x+11=10×7

⇒ 14y+x+11=70

⇒ 14y+x=70−11

⇒ 14y+x=59 ....(iii)

Substituting y = 33x - 95 in (iii), we get

14(33x - 95) + x = 59

⇒ 462x - 1330 + x = 59

⇒ 463x = 59 + 1330

⇒ 463x = 1389

⇒x=1389463=3

Putting x = 3, in y = 33x - 95, we get

y = 33 × 3 - 95

⇒ y = 99 - 95 = 4

⇒ y = 4

Hence, Solution of the given system of equation is x = 3, y = 4.

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