Question

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Answer 1

Answer:

Molar mass of Al = 27 g mol

Hence 27g Al = 1 mol

1 Al³+ = 3 electrons

1 mol Al³+ = 3 mol electrons

1 mol electrons = 1 Faraday

Hence 1 mol Al³+ =1F

Answer 2

$\huge{\underline{\mathfrak{\red {\ ANSWER;}}}}$

Atomic mass of Al = 27

No. of moles Al =27/27

= 1 mole

Charge on 1 Al3- ion = 3 e -

1 e = 1.602×10^19Coulombs

= -3 × 1.602×10^19Coulombs

Now, Charge on 1 mole Al3- ions

= -3 × 1.602×10^19 × 6.022×10^23Coulombs

= -2.894×105 Coulombs.