Math, asked by kc41622, 5 hours ago

please have this question

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Answered by Uditpatagar1221

1

Step-by-step explanation:

Given, 1/ tan3A+tanA1+ 1/cot3A+cotA1

=kcot2A

LHS=cos3Asin3A−cosAsinA1−sin3Acos3A−sinAcosA1

=sin2Acos3AcosA+sin2Asin3AsinA

=cot2A

So, k=1

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