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Let α and β be their zeroes.
Given, α = 1 / β.
In this quadratic polynomial,
Coefficient of x² = ( a² + a )
Coefficient of x = 3
Constant term = 6a.
We know that,
Product of zeroes = constant term ÷ coefficient of x²
⇒ α × 1/α = 6a ÷ ( a² + a )
⇒ 1 = 6a ÷ a ( a + 1 )
⇒ 1 = 6 / ( a + 1 )
⇒ ( a + 1 ) = 6.
⇒ a = 6 - 1
∴ a = 5.
Given, α = 1 / β.
In this quadratic polynomial,
Coefficient of x² = ( a² + a )
Coefficient of x = 3
Constant term = 6a.
We know that,
Product of zeroes = constant term ÷ coefficient of x²
⇒ α × 1/α = 6a ÷ ( a² + a )
⇒ 1 = 6a ÷ a ( a + 1 )
⇒ 1 = 6 / ( a + 1 )
⇒ ( a + 1 ) = 6.
⇒ a = 6 - 1
∴ a = 5.
sleepoholic:
dhanyavad!!! T_T ≥﹏≤ we needed this!!!
thank you so so sooooooooooooooo much
Thanks
bhai agli bar bhi aap maths mai help Karna
Thik hay bhai
oh bhai, Meeko bhi help kariyo, mera intention nhi tha Ha contradict karne ka!!
Kya ?
chal chod, kuch nhi! :-D
Thik hay
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