Question

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# Please help #


1) Calculate the molality of 1 litre solution of 93% h2so4. ( mass / volume ). The density of the solution is 1.84 g/mL. [ molecular mass of h2so4 =98 ]


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@ Prabhu dutt......

Answer 1

Your answer is ---


Let ,

100ml solution contain = 93 gram H2SO4

So, 1L solution contain = 930 gm H2SO4

since, density of the solution is 1.84 g/mL.

i.e, 1 ml solution contain = 1.84 g solution

1L solution contain = 1840 g solution .

Now,
mass of H2SO4 in 1L solution is 930 g

and

mass of solution in 1L is 1840 g

So , mass of solvent = 1840 - 930 = 910 g or 0.91Kg


We know that

molality = no. of mole of solute/mass of solvent in kg

Now, mol of H2SO4 = 930/98 = 9.49mol

put this value ,


Therefore ,


molality = 9.49/0.91 = 10.43m


Hence, molality of solution is 10.43m



【 Hope it helps you 】

Answer 2

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