Please Help...............
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Area of the figure= area of the triangle+ area of the trapezium
=(base×height)/2 + (sum of lengths of parallel side ) height /2
=(18×12)/2 +(18+14)(17-12)/2
=108+80
=188 sq units
=(base×height)/2 + (sum of lengths of parallel side ) height /2
=(18×12)/2 +(18+14)(17-12)/2
=108+80
=188 sq units
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