Question

please help..........​

Answer 1

Answer:

Please mark as brainliest if you understood

Explanation:

22.Given that,

Current, I = 5 A

Time, t = 2 minutes = 120 seconds

The charge Q is gets transferred. It is given by :

Q = It

Q = 600 coulombs

So, the transferred charge is 600 coulombs. Hence, this is the required solution.

23.

Answer :

300C

Solution :

Q=It=0.5A×(10×60)s=300C

24.Given:

For electric bulb:

Voltage = 220 V

Resistance = 1200 Ω

Solution:

According to Ohm's law, the current is ratio of voltage and resistance, hence, can be written as:

I=V/R

Plug the given values in the above formula:

I=220/1200

=0.183 A

Answer 2

22. Given that,

Current, I = 5 A

Time, t = 2 minutes = 120 seconds

The charge Q is gets transferred. It is given by :

I = Q/t

Q = It

Q = 5*120

Q = 600 coulombs

So, the transferred charge is 600 coulombs. Hence, this is the required solution.

23. Current, I = 0.5 A

Time, t = 10 minute = 10×60 = 600 seconds

Let the total charge flown = Q

I = Q/t

Q = It

Q = 0.5*600 C

Q = 300 C

24. Given,

Voltage(V) = 220 V

Resistance(R) = 1200 Ω

V = IR  

I = V/R = 220/1200

I = 0.1833 A