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this is the answer of that question and pls. change the alpabets of this question
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In triangle ABX,
AB+BC>AX-(1) ( sum of two sides is greater than the third side)
In triangle ACX
AC+CX>AX-(2)
From 1and 2 we get,
AB+BC+AC+CX>2AX
Hence, proved.
AB+BC>AX-(1) ( sum of two sides is greater than the third side)
In triangle ACX
AC+CX>AX-(2)
From 1and 2 we get,
AB+BC+AC+CX>2AX
Hence, proved.
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