Math, asked by jyotismita39, 1 month ago

please help........,......​

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Answered by nagathegenius
0

Step-by-step explanation:

mod z=root 17 / root 10

(x+w)(x+w^2)

x^2-(-w-w^2)x+1=0

x^2-x+1=0

mod z+6 = mod 2z+3

mod z+6= 2 mod z+1.5

(mod z+6)^2=4(mod z+1.5)^2

(z+6)(Z+6)=4(z+1.5)(Z+1.5)

zZ+6(z+Z)+36 = 4(zZ+1.5(z+Z)+2.25)

3Zz=27

zZ=9

5+2i/-1+root3 i

5+2i*-1-root3 i)/2

-1/2(5+2i)(1+root3 i)

-1/2(5-2root3 +i(2+5root3) )

+-2{root mod z+a / 2 }

+-2{2}

+-4

Answered by udayagrawal49
1

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Please refer to the attachments.

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