Math, asked by swara1804, 5 months ago

Please help
521 X 4854 =
522 X 34 =
287 X 2550 =
604 X 82=
862 X 3457 =
831 X 37 =
852 X 3522 =
316 X 52 =
375 X 3272 =
911 X 28 =
357 X 2709 =
128 X 67 =
202 X 8812 =
935 X 42 =
375 X 6742 =
812 X 96 =
335 X 8465 =
547 x 88 =
876 X 9538 =
439 X 92=
895 X 6821 =
624 X 82=
625 X 5248 =
871 X 49 =​

Answers

Answered by bachanar7
0

Answer:

bsnak

Step-by-step explanation:

852 X 3522 =

316 X 52 =

375 X 3272 =

911 X 28 =

357 X 2709 =

128 X 67 =

202 X 8812 =

935 X 42 =

375 X 6742 =

812 X 96 =

335 X 8465 =

547 x 88 =

876 X 9538 =

439 X 92=

895 X 6821 =

624 X 82=

625 X 5248 =

871

Answered by Anonymous
2

Answer:

hello

Find the areas of rectangles with the following pairs of monomials as their lengths and breadths respectively:

(p, q); (10m, 5n); (20x2, 5y2); (4x, 3x2);

(3mn, 4np)

Sol. We know that the area of a rectangle = l × b, where l = length and b = breadth.

Therefore, the areas of rectangles with pair of monomials (p, q); (10m, 5n); (20x2, 5y2);

(4x, 3x2) and (3mn, 4np) as their lengths and breadths are given by

p × q = pq

10m × 5n = (10 × 5) × (m × n) = 50mn

20x2 × 5y2 = (20 × 5) × (x2 × y2)

= 100x2y2

4x × 3x2 = (4 × 3) × (x × x2)

= 12x3

and, 3mn × 4np = (3 × 4) × (m × n × n )

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