Question

please help......................

Answer 1

may be this can help you

Answer 2

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$\color{indigo}Required \: \: Answer$

Evaluate:-

3sin²A+5sec²A+3cos²A-5tan²A

Arrange in particular form

$3 \sin {}^{2}a + 3cos {}^{2} a +5sec {}^{2}a - 5tan {}^{2} a$

Taking CommOn

3(Sin²A+Cos²A)+5(Sec²A-tan²A)

We know that..

Sin²∅+cos ²∅=1

Also------

Sec²∅-tan²∅

Then,

3(Sin²A+Cos²A)+5(Sec²A-tan²A)

=)3(1)+5(1)

=)3+5

=). 8

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