Question

please help!!☺☺...........​

Answer 1

Answer:

283.9 cm²

Step-by-step explanation:

From figure:

∠BOD = 90°

∠CAB = 90°

In ΔCAB,

⇒ (AC)² + (AB)² = (BC)²

⇒ (24)² + (7)² = (BC)²

⇒ 576 + 49 = BC²

⇒ BC = 25 cm.

(i) Area of circle:

= πr²

= (22/7) * (25/2)²

= 6875/14 cm²

(ii) Area of ΔCAB:

= (1/2) * AC * AB

= (1/2) * 24 * 7

= 84 cm²

(iii) Area of sector COD:

∴ ∠COD + ∠BOD = 180°

⇒ ∠COD = 180° - 90° = 90°

Now,

= θ/360(πr²)

= (90/360°)[(22/7) * (25/2)²]

= (1/4) * 22/7 * 625/4

= 6875/56 cm²

∴ Area of shaded region:

= (6875/14) - 84 - (6875/56)

= 283.9 cm²

Hope it helps!

Answer 2

The answer is explained in the attachment.