Please help! 88 students took part in an English competition. 72 of them were men. What percentage of all participants were men?
gunjancomic9:
81.81
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Answered by
4
Total number of participants = 88
Number of men = 72
Percentage of men = 72/88*100 =81.818181... = 81.82 %
Therefore, 81.82% of men were present among the participants.
Number of men = 72
Percentage of men = 72/88*100 =81.818181... = 81.82 %
Therefore, 81.82% of men were present among the participants.
Answered by
2
Number of men = 72
Number of students = 88
Percentage = (Number of men÷Number of students)×100
72÷88×100
=81.8%
Hope it helps..
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