Question

please help!!!

Answer with steps

Answer 1

[a²(a-3)-a²+a+6]/(a-3),

[a²(a-3)-a(a-3)-2a+6]/(a-3),

[a²(a-3)-a(a-3)-2(a-3)]/(a-3),

[(a-3)(a²-a-2)]/(a-3),

then it becomes

(a²-a-2),

a²-(2-1)a-2,

a²-2a+a-2,

a(a-2)+1(a-2),

(a-2)(a+1)