Please help asap. I will definitely mark as brainliest
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4a² + 9b² +12ab -c² =0
(2a)² + (3c)² +2(2a)(3b) -c² =0
(2a +3b)² -c² =0
(2a + 3b -c)(2a +3b +c) =0
2a + 3b =c or -c
ax + by + c =0
ax + by +2a +3b =0
a( x +2) + b( y +3) =0
hence, at x = -2 , y = -3 (-2, -3)
or ,
ax + by +(-2a -3b) =0
a(x -2) +b( y -3)=0
so, at point (2, 3)
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please don't delete the answer it's right
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