Question

Please help ASAP❗

No spam❌

Answer 1

pls check the attachment

Answer 2

I am taking different roots as:
X= 2/3, -1/2

So, The equation can be formed as:

(x - 2/3) (x - (-1/2)) = 0

x² -(2/3 - 1/2)x + (2/3)(-1/2) = 0

x² - (1/6)x - 1/3 = 0

method 2:

$let \alpha = 2 \div 3 \\ \beta = - 1 \div 2 \\ be \: the \: two \: roots \: of \: the \: quadratic \: equation. \\ so \: quadratic \: equation \: can \: be \: written \: as \\ {x}^{2} - \: ( \alpha + \beta )x \: + \alpha \beta \: = \: 0 \\ hence \: the \: quadratic \: equation \: is \\ {x}^{2} - (1 \div 6)x \: - 1 \div 3 \: = 0$

If you understood the process, do the question yourself.


Thankyou!!!